m = 500, g
C6H12O6
1, mol
=
V = ?, l
2CO2
2, mol
+
2C2H5OH
| m (C6H12O6) | 500 | |||||
| n(C6H12O6) | = | = | = | 2.78 (mol) | ||
| Mr(C6H12O6) | 180.18 |
| 2.78 | x | |
| = | ||
| 1 | 2 |
1x = 2.78 × 2;
| 2.78 · 2 | ||||
| x | = | = | 5.56 (mol); | |
| 1 |
V(CO2) = n(CO2) × Vm = 5.56 × 22.4 = 124.544 (l);
Answer: 124.544 l.